(\partial)/(\partial y)(2e^{2z}xy-2y)

Lösung

\frac{\partial}{\partial y} (2 e^{2 z} x y - 2 y)

2 x e^{2 z} - 2

Schritte zur Lösung

\frac{\partial}{\partial y} (2 e^{2 z} x y - 2 y)

Behandle

z, x

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 e^{2 z} x y) - \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (2 e^{2 z} x y) = 2 x e^{2 z}

\frac{\partial}{\partial y} (2 y) = 2

= 2 x e^{2 z} - 2

t a y l or \frac{1}{x ^{3}}

\frac{d}{d t} (cos (t) - sin (t))

\int + \frac{e ^{2 x}}{1 + e ^{2 x}} d x

t an g e n t f (x) = 4 x^{2} - 4 x + 1, at x = 1

\frac{\partial}{\partial x} (x sin (x + y) - cos (x + y))