What is the derivative of (x-3^3) ?

The derivative of (x-3^3) is 3(x-3)^2

What is the first derivative of (x-3^3) ?

The first derivative of (x-3^3) is 3(x-3)^2

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\frac{d}{d x} ((x - 3)^{3})

3 (x - 3)^{2}

Solution steps

\frac{d}{d x} ((x - 3)^{3})

Apply the chain rule:

3 (x - 3)^{2} \frac{d}{d x} (x - 3)

= 3 (x - 3)^{2} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= 3 (x - 3)^{2} \cdot 1

Simplify

= 3 (x - 3)^{2}

y^{^{'}} = \frac{3 x ^{2} - 1}{3 + 2 y}

\frac{d}{d x} (a x sin (k x) + b x cos (k x))

f (x) = 5 x + 2

f (x) = - 2 ln (x) + x^{2} - 4 + e^{x} + x^{e}

\frac{d}{d x} (2^{l n (x)})

What is the derivative of (x-3^3) ?
The derivative of (x-3^3) is 3(x-3)^2
What is the first derivative of (x-3^3) ?
The first derivative of (x-3^3) is 3(x-3)^2