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人気のある微分積分 >

f^'(x)=2^x

解

f^{^{'}} (x) = 2^{x}

解

f (x) = \frac{2 ^{x}}{ln ( 2 )} + c_{1}

解答ステップ

f^{'} (x) = 2^{x}

f^{^{'}} (x) = g (x)

であれば

f (x) = \int g (x) d x

f (x) = \int 2^{x} d x

\int 2^{x} d x = \frac{2 ^{x}}{ln ( 2 )} + c_{1}

f (x) = \frac{2 ^{x}}{ln ( 2 )} + c_{1}

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