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tangent f(x)=x^2+2,(-3,11)

解答

切线

f (x) = x^{2} + 2, (- 3, 11)

解答

y = - 6 x - 7

求解步骤

计算

f (x) = x^{2} + 2

的斜率:

\frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6

找到斜率 m=

- 6

且穿过

(- 3, 11)

的直线:

y = - 6 x - 7

y = - 6 x - 7

作图

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