(\partial)/(\partial x)(36-6x^2-y^2)

解答

\frac{\partial}{\partial x} (36 - 6 x^{2} - y^{2})

- 12 x

求解步骤

\frac{\partial}{\partial x} (36 - 6 x^{2} - y^{2})

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (36) - \frac{\partial}{\partial x} (6 x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (36) = 0

\frac{\partial}{\partial x} (6 x^{2}) = 12 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 0 - 12 x - 0

化简

= - 12 x

t a y l or \frac{2 x}{e ^{2 x^{2}} - 1}

\frac{d}{d x} (23 sin (x) + 2 cos (x))

\int_{1}^{2} 3 d x

s l o p e (x^{2} + y^{2})^{2} = 4 x^{2} y, (- 1, 1)

x \to 0 lim (\frac{x + 2}{x})