What is the derivative of Ax^2+Bx ?

The derivative of Ax^2+Bx is 2Ax+B

What is the first derivative of Ax^2+Bx ?

The first derivative of Ax^2+Bx is 2Ax+B

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (A x^{2} + B x)

2 A x + B

Solution steps

\frac{d}{d x} (A x^{2} + B x)

Treat

A, B

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (A x^{2}) + \frac{d}{d x} (B x)

\frac{d}{d x} (A x^{2}) = 2 A x

\frac{d}{d x} (B x) = B

= 2 A x + B

\int cos (5 x) sin (6 x) d x

\int x x + 3 d x

\frac{d y}{d x} = \frac{( x + 3 y )}{y - 3 x}

x \to 3 lim (\frac{x ^{3} - 6 x ^{2} + 9}{x ^{2} - 9})

y = 7 x - 4 x^{2}, (- 3, - 57)

What is the derivative of Ax^2+Bx ?
The derivative of Ax^2+Bx is 2Ax+B
What is the first derivative of Ax^2+Bx ?
The first derivative of Ax^2+Bx is 2Ax+B