(\partial)/(\partial x)(x^2-xy-y^2)

Lösung

\frac{\partial}{\partial x} (x^{2} - x y - y^{2})

2 x - y

Schritte zur Lösung

\frac{\partial}{\partial x} (x^{2} - x y - y^{2})

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 x - y - 0

Vereinfache

= 2 x - y

\frac{d y}{d x} = x y + 3 x + 5 y + 15

\frac{d}{d x} (\frac{5 ^{x}}{1 + 5 ^{2 x}})

\int_{\frac{1}{7}}^{5} 16 x ln (7 x) d x

\frac{d}{d x} ((x)^{\frac{1}{2}})

\int_{- 2}^{2} x^{3} cos (\frac{x}{2}) + \frac{1}{2} d x