(xy^2-x)dx+(x^2y+y)dy=0

Lösung

(x y^{2} - x) d x + (x^{2} y + y) d y = 0

y = \frac{c _{1} + x ^{2} + 1}{x ^{2} + 1}, y = - \frac{c _{1} + x ^{2} + 1}{x ^{2} + 1}

Schritte zur Lösung

(x y^{2} - x) d x + (x^{2} y + y) d y = 0

Solve separable ODE:

y = \frac{c _{1} + x ^{2} + 1}{x ^{2} + 1}, y = - \frac{c _{1} + x ^{2} + 1}{x ^{2} + 1}

y = \frac{c _{1} + x ^{2} + 1}{x ^{2} + 1}, y = - \frac{c _{1} + x ^{2} + 1}{x ^{2} + 1}

\frac{\partial}{\partial x} (20 - 2 x + 1.5 - x + 3 x)

\frac{d ^{2}}{d x ^{2}} (- 8 sin (\frac{3 x}{2} + 1))

\frac{\partial}{\partial t} (x e^{- t} sin (θ))

x \to 0 + lim (\frac{1}{x ^{2}} + ln (x))

\int \frac{- 10}{x ^{2} ( 25 - x ^{2} ) ^{\frac{1}{2}}} d x