What is the derivative of f(x)=-8sin(x) ?

The derivative of f(x)=-8sin(x) is -8cos(x)

What is the first derivative of f(x)=-8sin(x) ?

The first derivative of f(x)=-8sin(x) is -8cos(x)

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derivative of

f (x) = - 8 sin (x)

- 8 cos (x)

Solution steps

\frac{d}{d x} (- 8 sin (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (sin (x))

Apply the common derivative:

\frac{d}{d x} (sin (x)) = cos (x)

= - 8 cos (x)

\int (z^{2}) d z

\frac{\partial}{\partial x} (\frac{1}{x} + \frac{1}{1 - x})

\int (- 2 cos (x)) d x

\int sin (\frac{t}{2}) t d t

1 - x^{2}, - 1, 1

What is the derivative of f(x)=-8sin(x) ?
The derivative of f(x)=-8sin(x) is -8cos(x)
What is the first derivative of f(x)=-8sin(x) ?
The first derivative of f(x)=-8sin(x) is -8cos(x)