integral of (x-8)^2

Lösung

\int (x - 8)^{2} d x

\frac{x ^{3}}{3} - 8 x^{2} + 64 x + C

Schritte zur Lösung

\int (x - 8)^{2} d x

Multipliziere aus

(x - 8)^{2} : x^{2} - 16 x + 64

= \int x^{2} - 16 x + 64 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 16 x d x + \int 64 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 16 x d x = 8 x^{2}

\int 64 d x = 64 x

= \frac{x ^{3}}{3} - 8 x^{2} + 64 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} - 8 x^{2} + 64 x + C

in v erse l a pl a ce \frac{3}{s} (1 - e^{- s})

\int_{1}^{2} (3 - e^{x}) d x

y^{^{''}} + 4 y = e^{t} (cos (2 t) + sin (2 t))

d er i v a t i v e f (x) = - 7 x^{2}

x \to 0 lim ((ln (\frac{1}{x}))^{x})