integral from 0 to pi/(24) of cos(4x)

Lösung

\int_{0}^{\frac{π}{24}} cos (4 x) d x

\frac{1}{8}

Dezimale

0.125

Schritte zur Lösung

\int_{0}^{\frac{π}{24}} cos (4 x) d x

Wende U-Substitution an

= \int_{0}^{\frac{π}{6}} cos (u) \frac{1}{4} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{0}^{\frac{π}{6}} cos (u) d u

Nutze das gemeinsame Integral :

\int cos (u) d u = sin (u)

= \frac{1}{4} [sin (u)]_{0}^{\frac{π}{6}}

Berechne die Grenzen:

\frac{1}{2}

= \frac{1}{4} \cdot \frac{1}{2}

Vereinfache

= \frac{1}{8}

\int 9 + 16 t^{2} d t

x \to 3 lim (\frac{1 - x}{x - 3})

\frac{\partial}{\partial y} (x^{2} + 2 y)

\frac{d}{d x} (x^{n} (ln (x))^{2})

d er i v a t i v e f (x) = \frac{9 - x e ^{x}}{x + e ^{x}}