What is the solution for y^'-((2x)/((1+x^2)))y=0 ?

The solution for y^'-((2x)/((1+x^2)))y=0 is y=e^{c_{1}}x^2+e^{c_{1}}

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y^'-((2x)/((1+x^2)))y=0

y^{^{'}} - (\frac{2 x}{( 1 + x ^{2} )}) y = 0

y = e^{c_{1}} x^{2} + e^{c_{1}}

Solution steps

y^{'} (x) - (\frac{2 x}{( 1 + x ^{2} )}) y = 0

Solve separable ODE:

y = e^{c_{1}} x^{2} + e^{c_{1}}

y = e^{c_{1}} x^{2} + e^{c_{1}}

\int ln (e^{u^{2}}) d u

3 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0

x \to 3 lim (x^{2} - 4 x)

\int \frac{4}{4 x - 1} d x

\frac{d}{d x} (t a g (t, x) x)

What is the solution for y^'-((2x)/((1+x^2)))y=0 ?
The solution for y^'-((2x)/((1+x^2)))y=0 is y=e^{c_{1}}x^2+e^{c_{1}}