What is the first derivative of x^2-5 ?

The first derivative of x^2-5 is 2x

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derivative of x^2-5

derivative of

x^{2} - 5

2 x

Solution steps

\frac{d}{d x} (x^{2} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5) = 0

= 2 x - 0

Simplify

= 2 x

\frac{d}{d x} ((2 x)^{3 x})

\frac{d}{d x} (5 x - 9)

y^{^{''}} - 5 y^{^{'}} + 6 y = sin (x)

\int sec^{2} (3 θ) d θ

x \to 8 - lim (\frac{x}{ln ( 9 - x )})