What is the derivative of-2x-3x^3 ?

The derivative of-2x-3x^3 is -2-9x^2

What is the first derivative of-2x-3x^3 ?

The first derivative of-2x-3x^3 is -2-9x^2

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\frac{d}{d x} (- 2 x - 3 x^{3})

- 2 - 9 x^{2}

Solution steps

\frac{d}{d x} (- 2 x - 3 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x) - \frac{d}{d x} (3 x^{3})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

= - 2 - 9 x^{2}

cos (\frac{1}{4} t)

\int (1 + 3 x) d x

\frac{\partial}{\partial z} (x - y)

\int \frac{x + 3}{4 x + 4} d x

cos (\frac{2}{3} x)

What is the derivative of-2x-3x^3 ?
The derivative of-2x-3x^3 is -2-9x^2
What is the first derivative of-2x-3x^3 ?
The first derivative of-2x-3x^3 is -2-9x^2