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Popular >

derivative of 2sin(2x-4sin^9(2x))

Solution

\frac{d}{d x} (2 sin (2 x) - 4 sin^{9} (2 x))

Solution

4 cos (2 x) - 72 sin^{8} (2 x) cos (2 x)

Solution steps

\frac{d}{d x} (2 sin (2 x) - 4 sin^{9} (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sin (2 x)) - \frac{d}{d x} (4 sin^{9} (2 x))

\frac{d}{d x} (2 sin (2 x)) = 4 cos (2 x)

\frac{d}{d x} (4 sin^{9} (2 x)) = 72 sin^{8} (2 x) cos (2 x)

= 4 cos (2 x) - 72 sin^{8} (2 x) cos (2 x)

Popular Examples

derivative of x^{2/3}(5-x)

\frac{d}{d x} (x^{\frac{2}{3}} (5 - x))

area 19-x^2,-2x+16,-5,-sqrt(19)area

19 - x^{2}, - 2 x + 16, - 5, - 19

(\partial)/(\partial x)(y*sqrt(|x|))

\frac{\partial}{\partial x} (y \cdot ∣ x ∣)

(x^2+1)y^'+9x(y-1)=0,y(0)=2

(x^{2} + 1) y^{^{'}} + 9 x (y - 1) = 0, y (0) = 2

\frac{d P}{d t} - a P = b

Frequently Asked Questions (FAQ)

What is the derivative of 2sin(2x-4sin^9(2x)) ?
The derivative of 2sin(2x-4sin^9(2x)) is 4cos(2x)-72sin^8(2x)cos(2x)
What is the first derivative of 2sin(2x-4sin^9(2x)) ?
The first derivative of 2sin(2x-4sin^9(2x)) is 4cos(2x)-72sin^8(2x)cos(2x)