(9x^2+y-1)dx-(4y-x)dy=0

Lösung

(9 x^{2} + y - 1) d x - (4 y - x) d y = 0

y = - \frac{- x + x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}, y = - \frac{- x - x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}

Schritte zur Lösung

(9 x^{2} + y - 1) d x - (4 y - x) d y = 0

Solve exact ODE:

y = - \frac{- x + x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}, y = - \frac{- x - x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}

y = - \frac{- x + x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}, y = - \frac{- x - x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}

\frac{\partial}{\partial x} (1 + ln (x) + \frac{y}{x})

x \to \infty lim (\frac{ln ( x )}{3 x})

ma c l a u r in \frac{1}{x - 1}

\frac{\partial}{\partial x} (x^{4} + y^{4} - 4 x + 1 y)

t an g e n t f (x) = 5 x^{\frac{1}{2}} + x^{\frac{3}{2}}, at x = 4