What is the solution for (dy)/(dx)=((x+y)^2)/(2x^2) ?

The solution for (dy)/(dx)=((x+y)^2)/(2x^2) is y=tan(1/2 ln(x)+c_{1})x

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(dy)/(dx)=((x+y)^2)/(2x^2)

\frac{d y}{d x} = \frac{( x + y ) ^{2}}{2 x ^{2}}

y = tan (\frac{1}{2} ln (x) + c_{1}) x

Solution steps

\frac{d y}{d x} = \frac{( x + y ) ^{2}}{2 x ^{2}}

Solve using substitution:

y = tan (\frac{1}{2} ln (x) + c_{1}) x

y = tan (\frac{1}{2} ln (x) + c_{1}) x

\frac{d}{d x} (x^{2} - 4 x y + y^{2})

x^{2} y^{^{'}} + x y = 9

\frac{d}{d x} (ln (x) (x - 1))

\frac{d y}{d x}, 5 cos (8 x) sin (5 y) = 8

y^{^{''}} = 12 t - 2

What is the solution for (dy)/(dx)=((x+y)^2)/(2x^2) ?
The solution for (dy)/(dx)=((x+y)^2)/(2x^2) is y=tan(1/2 ln(x)+c_{1})x