integral of (7x+1)(7x^2+2x)^{3/4}

Lösung

\int (7 x + 1) (7 x^{2} + 2 x)^{\frac{3}{4}} d x

\frac{2}{7} (7 x^{2} + 2 x)^{\frac{7}{4}} + C

Schritte zur Lösung

\int (7 x + 1) (7 x^{2} + 2 x)^{\frac{3}{4}} d x

Wende U-Substitution an

= \int \frac{u ^{\frac{3}{4}}}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int u^{\frac{3}{4}} d u

Wende die Potenzregel an

= \frac{1}{2} \cdot \frac{4}{7} u^{\frac{7}{4}}

Setze in

u = 7 x^{2} + 2 x

ein

= \frac{1}{2} \cdot \frac{4}{7} (7 x^{2} + 2 x)^{\frac{7}{4}}

Vereinfache

\frac{1}{2} \cdot \frac{4}{7} (7 x^{2} + 2 x)^{\frac{7}{4}} : \frac{2}{7} (7 x^{2} + 2 x)^{\frac{7}{4}}

= \frac{2}{7} (7 x^{2} + 2 x)^{\frac{7}{4}}

Füge eine Konstante zur Lösung hinzu

= \frac{2}{7} (7 x^{2} + 2 x)^{\frac{7}{4}} + C

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