What is the derivative of f(x)=(6x^2-9x)e^x ?

The derivative of f(x)=(6x^2-9x)e^x is 6e^xx^2+3e^xx-9e^x

What is the first derivative of f(x)=(6x^2-9x)e^x ?

The first derivative of f(x)=(6x^2-9x)e^x is 6e^xx^2+3e^xx-9e^x

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derivative of

f (x) = (6 x^{2} - 9 x) e^{x}

6 e^{x} x^{2} + 3 e^{x} x - 9 e^{x}

Solution steps

\frac{d}{d x} ((6 x^{2} - 9 x) e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 6 x^{2} - 9 x, g = e^{x}

= \frac{d}{d x} (6 x^{2} - 9 x) e^{x} + \frac{d}{d x} (e^{x}) (6 x^{2} - 9 x)

\frac{d}{d x} (6 x^{2} - 9 x) = 12 x - 9

\frac{d}{d x} (e^{x}) = e^{x}

= (12 x - 9) e^{x} + e^{x} (6 x^{2} - 9 x)

Simplify

(12 x - 9) e^{x} + e^{x} (6 x^{2} - 9 x) : 6 e^{x} x^{2} + 3 e^{x} x - 9 e^{x}

= 6 e^{x} x^{2} + 3 e^{x} x - 9 e^{x}

\frac{d}{d x} (\frac{( x ^{2} )}{x ^{2} + 1})

n = 1 \sum \infty (\frac{1}{6})^{n}

x^{2} + 8 x - 7

\frac{9 x}{2 ^{x}}

y = 4 x^{2} + 2

What is the derivative of f(x)=(6x^2-9x)e^x ?
The derivative of f(x)=(6x^2-9x)e^x is 6e^xx^2+3e^xx-9e^x
What is the first derivative of f(x)=(6x^2-9x)e^x ?
The first derivative of f(x)=(6x^2-9x)e^x is 6e^xx^2+3e^xx-9e^x