What is the derivative of 3^xln(3) ?

The derivative of 3^xln(3) is ln^2(3)*3^x

What is the first derivative of 3^xln(3) ?

The first derivative of 3^xln(3) is ln^2(3)*3^x

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derivative of

3^{x} ln (3)

ln^{2} (3) \cdot 3^{x}

Solution steps

\frac{d}{d x} (3^{x} ln (3))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= ln (3) \frac{d}{d x} (3^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= ln (3) \cdot 3^{x} ln (3)

Simplify

ln (3) \cdot 3^{x} ln (3) : ln^{2} (3) \cdot 3^{x}

= ln^{2} (3) \cdot 3^{x}

\int_{1}^{2} 4 r^{2} ln (r) d r

\frac{d}{d x} (ln (\frac{x - 2}{x + 1}))

\int (2 - x)^{2} ln (4 x) d x

\frac{11}{3} t^{3} + 11 t^{2}

What is the derivative of 3^xln(3) ?
The derivative of 3^xln(3) is ln^2(3)*3^x
What is the first derivative of 3^xln(3) ?
The first derivative of 3^xln(3) is ln^2(3)*3^x