What is the limit as y approaches infinity of 1/5 (2y^2+3y)x ?

The limit as y approaches infinity of 1/5 (2y^2+3y)x is infinity

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limit as y approaches infinity of 1/5 (2y^2+3y)x

y \to \infty lim (\frac{1}{5} (2 y^{2} + 3 y) x)

\infty

Solution steps

y \to \infty lim (\frac{1}{5} (2 y^{2} + 3 y) x)

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= \frac{1}{5} x \cdot y \to \infty lim (2 y^{2} + 3 y)

Simplify

\frac{1}{5} x : \frac{x}{5}

= \frac{x}{5} \cdot y \to \infty lim (2 y^{2} + 3 y)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= \frac{x}{5} (y \to \infty lim (2 y^{2}) + y \to \infty lim (3 y))

y \to \infty lim (2 y^{2}) = \infty

y \to \infty lim (3 y) = \infty

= \frac{x}{5} (\infty + \infty)

Simplify

\frac{x}{5} (\infty + \infty) : \infty

= \infty

2 - x^{2}, 10 - 6 x

\int_{0}^{0.4} 300 x d x

\frac{d}{d x} (x^{2} lo g_{2} (x^{3}))

u^{5}

What is the limit as y approaches infinity of 1/5 (2y^2+3y)x ?
The limit as y approaches infinity of 1/5 (2y^2+3y)x is infinity