What is the derivative of (a+bx^3) ?

The derivative of (a+bx^3) is 3(a+bx)^2b

What is the first derivative of (a+bx^3) ?

The first derivative of (a+bx^3) is 3(a+bx)^2b

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\frac{d}{d x} ((a + b x)^{3})

3 (a + b x)^{2} b

Solution steps

\frac{d}{d x} ((a + b x)^{3})

Apply the chain rule:

3 (a + b x)^{2} \frac{d}{d x} (a + b x)

= 3 (a + b x)^{2} \frac{d}{d x} (a + b x)

\frac{d}{d x} (a + b x) = b

= 3 (a + b x)^{2} b

x \to 2 lim (x^{2} - 4 x + 1)

\int \frac{1}{( 1 + x ^{4} )} d x

\int \frac{x ^{4}}{( 7 + x ^{5} ) ^{2}} d x

n = 2 \sum \infty \frac{3 ^{n}}{1 2 ^{n}}

4 y^{^{''}} - 4 y^{^{'}} + y = 8 e^{\frac{x}{2}}

What is the derivative of (a+bx^3) ?
The derivative of (a+bx^3) is 3(a+bx)^2b
What is the first derivative of (a+bx^3) ?
The first derivative of (a+bx^3) is 3(a+bx)^2b