What is (\partial)/(\partial x)(y^2ln(x)) ?

The answer to (\partial)/(\partial x)(y^2ln(x)) is (y^2)/x

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(\partial)/(\partial x)(y^2ln(x))

\frac{\partial}{\partial x} (y^{2} ln (x))

\frac{y ^{2}}{x}

Solution steps

\frac{\partial}{\partial x} (y^{2} ln (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} \frac{\partial}{\partial x} (ln (x))

Apply the common derivative:

\frac{\partial}{\partial x} (ln (x)) = \frac{1}{x}

= y^{2} \frac{1}{x}

Simplify

y^{2} \frac{1}{x} : \frac{y ^{2}}{x}

= \frac{y ^{2}}{x}

\int \frac{x ^{6} - 5 x}{x ^{4}} d x

\frac{d}{d x} (e^{2} (sin (\frac{π}{4}) - 1))

\frac{s - 1}{2 s ^{2} + 8 s + 11}

1 + 5 x

\int \frac{x + 4}{x ^{3} + 3 x ^{2} + 2 x} d x

What is (\partial)/(\partial x)(y^2ln(x)) ?
The answer to (\partial)/(\partial x)(y^2ln(x)) is (y^2)/x