What is maclaurin ln(((1+x))/((1-x))) ?

The answer to maclaurin ln(((1+x))/((1-x))) is 2x+2/3 x^3+2/5 x^5+\ldots

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maclaurin ln(((1+x))/((1-x)))

maclaurin

ln (\frac{( 1 + x )}{( 1 - x )})

2 x + \frac{2}{3} x^{3} + \frac{2}{5} x^{5} + \dots

Solution steps

Apply the Maclaurin Formula

= 0 + \frac{\frac{d}{d x} ( ln ( \frac{1 + x}{1 - x} ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( ln ( \frac{1 + x}{1 - x} ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( ln ( \frac{1 + x}{1 - x} ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{2}{1 !} x + \frac{0}{2 !} x^{2} + \frac{4}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{48}{5 !} x^{5} + \dots

Refine

= 2 x + \frac{2}{3} x^{3} + \frac{2}{5} x^{5} + \dots

\frac{d}{d x} (- 3 e^{2 x})

\frac{1}{x ^{9}}

\int x (x^{2} - 3)^{4} d x

\frac{d}{d x} (- x + 3)

\frac{d}{d x} (\frac{- 4 x - 4 1 + x}{x ^{2} - 1})

What is maclaurin ln(((1+x))/((1-x))) ?
The answer to maclaurin ln(((1+x))/((1-x))) is 2x+2/3 x^3+2/5 x^5+\ldots