((x-1)^2)^'

Lösung

((x - 1)^{2})^{^{'}}

2 (x - 1)

Schritte zur Lösung

((x - 1)^{2})^{'}

Wende die Kettenregel an:

2 (x - 1) (x - 1)^{'}

= 2 (x - 1) (x - 1)^{'}

(x - 1)^{'} = 1

= 2 (x - 1) \cdot 1

Vereinfache

= 2 (x - 1)

\frac{\partial}{\partial z} (7 z e^{x yz})

d er i v a t i v e \frac{1}{( x ^{2} - 3 ) ( x ^{2} + 3 x + 5 )}

\frac{\partial}{\partial y} (y (y + sin (x)))

\int_{0}^{0.6} \frac{x ^{2}}{9 - 25 x ^{2}} d x

t an g e n t 2 x^{4} - 9 x^{2}