What is the sum from n=1 to infinity of arctan(3n) ?

The sum from n=1 to infinity of arctan(3n) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of arctan(3n)

n = 1 \sum \infty arctan (3 n)

diverges

Solution steps

n = 1 \sum \infty arctan (3 n)

Apply Series Divergence Test:

diverges

= diverges

\int - x + 2 x^{3} d x

\int 1 - 6 x d x

\int \frac{e ^{a r c s i n (x)}}{1 - x ^{2}} d x

\frac{d}{d x} (\frac{12}{x + 2} - 3)

\frac{d}{d x} (\frac{x ^{2} - 4 x}{x + 1})

What is the sum from n=1 to infinity of arctan(3n) ?
The sum from n=1 to infinity of arctan(3n) is diverges