f^'(x)=sqrt(x+1)

Lösung

f^{^{'}} (x) = x + 1

f (x) = \frac{2}{3} (x + 1)^{\frac{3}{2}} + c_{1}

Schritte zur Lösung

f^{'} (x) = x + 1

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

f (x) = \int x + 1 d x

\int x + 1 d x = \frac{2}{3} (x + 1)^{\frac{3}{2}} + c_{1}

f (x) = \frac{2}{3} (x + 1)^{\frac{3}{2}} + c_{1}

\frac{d}{d x} (- sin (2 x) \cdot 2 + cos (2 x) \cdot 2)

t an g e n t - 3 x^{2} + 6 x + 4

d er i v a t i v e f (x) = 2 e^{x} + \frac{2}{3 x}

n = 1 \sum \infty n^{5} (1 + n^{6})^{1}

\int \frac{z ^{3}}{3 5 + z ^{4}} d z