What is the first derivative of 1+2x^2 ?

The first derivative of 1+2x^2 is 4x

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derivative of 1+2x^2

derivative of

1 + 2 x^{2}

4 x

Solution steps

\frac{d}{d x} (1 + 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 x^{2}) = 4 x

= 0 + 4 x

Simplify

= 4 x

ln (3 + x)

\frac{d y}{d x} + y = e^{4 x}

\frac{d}{d x} (- \frac{2 x + 3}{( x ^{2} + 3 x + 2 ) ^{2}})

x \to 3 lim (3 x - 7)

\frac{1}{x ^{7}}