What is the integral from 0 to 6 of pi(3x)^2 ?

The integral from 0 to 6 of pi(3x)^2 is 648pi

Popular >

integral from 0 to 6 of pi(3x)^2

\int_{0}^{6} π (3 x)^{2} d x

648 π

Decimal Notation

2035.75203 \dots

Solution steps

\int_{0}^{6} π (3 x)^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{6} (3 x)^{2} d x

Simplify

(3 x)^{2} : 9 x^{2}

= π \cdot \int_{0}^{6} 9 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π 9 \cdot \int_{0}^{6} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{6}

= π 9 [\frac{x ^{3}}{3}]_{0}^{6}

Compute the boundaries:

72

= π 9 \cdot 72

Simplify

= 648 π

\int \frac{( ln ( u ) ) ^{8}}{u} d u

\frac{d y}{d x} = \frac{e ^{3 x} + 3 x y + y}{x}

\frac{d ^{2}}{d x ^{2}} (\frac{3 x - 2}{2 x + 1})

\frac{d}{d x} (\frac{lo g _{3} ( x )}{lo g _{7} ( x )})

\int x^{2} - cos (x) d x

What is the integral from 0 to 6 of pi(3x)^2 ?
The integral from 0 to 6 of pi(3x)^2 is 648pi