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Beliebt Rechnen >

6y^{''}-y^'-y=0,y(0)=10,y^'(0)=3

Lösung

6 y^{^{''}} - y^{^{'}} - y = 0, y (0) = 10, y^{^{'}} (0) = 3

Lösung

y = (10 - \frac{12}{5}) e^{\frac{t}{2}} + \frac{12}{5} e^{- \frac{t}{3}}

Schritte zur Lösung

6 y^{''} (t) - y^{'} (t) - y = 0

Solve linear ODE:

y = (10 - \frac{12}{5}) e^{\frac{t}{2}} + \frac{12}{5} e^{- \frac{t}{3}}

y = (10 - \frac{12}{5}) e^{\frac{t}{2}} + \frac{12}{5} e^{- \frac{t}{3}}

Graph

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