integral from 1 to 2 of (2x^3-4)

Lösung

\int_{1}^{2} (2 x^{3} - 4) d x

\frac{7}{2}

Dezimale

3.5

Schritte zur Lösung

\int_{1}^{2} 2 x^{3} - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x^{3} d x - \int_{1}^{2} 4 d x

\int_{1}^{2} 2 x^{3} d x = \frac{15}{2}

\int_{1}^{2} 4 d x = 4

= \frac{15}{2} - 4

Vereinfache

\frac{15}{2} - 4 : \frac{7}{2}

= \frac{7}{2}

d er i v a t i v e f (x) = (1 + 6 x^{2}) (x - x^{2})

n = 1 \sum \infty \frac{n x ^{n}}{n + 1}

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