integral of x^2+2x-4

Lösung

\int x^{2} + 2 x - 4 d x

\frac{x ^{3}}{3} + x^{2} - 4 x + C

Schritte zur Lösung

\int x^{2} + 2 x - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int 2 x d x - \int 4 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 2 x d x = x^{2}

\int 4 d x = 4 x

= \frac{x ^{3}}{3} + x^{2} - 4 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} + x^{2} - 4 x + C

\frac{\partial}{\partial y} (2 x^{3} - 11 x^{2} y + 3 y^{2})

\frac{\partial}{\partial x} (x - y + x y)

\frac{d}{d x} (\frac{6 x - 1}{3 x ^{2} - x})

\int \frac{5 x ^{4}}{x ^{5} + 8} d x

\int_{1}^{3} \frac{x}{x ^{2} + 1} d x