integral of-2.5-1/8 q

解答

\int - 2.5 - \frac{1}{8} q d q

- 2.5 q - 0.0625 q^{2} + C

求解步骤

\int - 2.5 - \frac{1}{8} q d q

化简

= \int - 2.5 - 0.125 q d q

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 2.5 d q - \int 0.125 q d q

\int 2.5 d q = 2.5 q

\int 0.125 q d q = 0.0625 q^{2}

= - 2.5 q - 0.0625 q^{2}

解答补常数

= - 2.5 q - 0.0625 q^{2} + C

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