y^'=2xsqrt(1-y^2)

Lösung

y^{^{'}} = 2 x 1 - y^{2}

y = sin (x^{2} + c_{1})

Schritte zur Lösung

y^{'} (x) = 2 x 1 - y^{2}

Solve separable ODE:

y = sin (x^{2} + c_{1})

y = sin (x^{2} + c_{1})

\frac{d}{d x} ((A x + B) e^{x})

y^{^{'}} + y = e^{9 t}, y (0) = - 1

x \to 2 lim (\frac{x + 3}{x + 2})

\frac{\partial}{\partial y} (x y^{3} + 4 y e^{x} - 2 y^{2})

\frac{\partial}{\partial y} (ln ((\frac{y}{x})^{2}))