(\partial)/(\partial y)(3x^2-5y)

解答

\frac{\partial}{\partial y} (3 x^{2} - 5 y)

- 5

求解步骤

\frac{\partial}{\partial y} (3 x^{2} - 5 y)

将

x

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) - \frac{\partial}{\partial y} (5 y)

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (5 y) = 5

= 0 - 5

化简

= - 5

y^{^{'}} = \frac{x y ^{2} - 0.5 sin ( 2 x )}{y ( 1 - x ^{2} )}

y^{^{'''}} + 2 y^{^{''}} + y^{^{'}} = 0

x \to a lim (9)

in v erse l a pl a ce \frac{2 s + 1}{s ^{2} + 2 s + 5}

t an g e n t y = x^{2} + x + 3, at x = 3.99