5x^2y^'=y^'+6xe^{-y}

Lösung

5 x^{2} y^{^{'}} = y^{^{'}} + 6 x e^{- y}

y = ln (\frac{3}{5} ln (5 x^{2} - 1) + c_{1})

Schritte zur Lösung

5 x^{2} y^{'} (x) = y^{'} (x) + 6 x e^{- y}

Solve separable ODE:

y = ln (\frac{3}{5} ln (5 x^{2} - 1) + c_{1})

y = ln (\frac{3}{5} ln (5 x^{2} - 1) + c_{1})

\frac{\partial}{\partial x} ((x^{2} + y^{2} + z^{2})^{- \frac{1}{4}})

x \to 0 lim (\frac{x - 2}{x})

\frac{\partial}{\partial y} (- 8 y^{3} + 4 x y + 4 x^{2} + 9 y^{2})

\frac{\partial}{\partial x} (\frac{x}{10} cos (5 x))

\int_{- 2}^{3} - x^{2} + x + 6 d x