laplacetransform 5(t-8)-10(t-4)

Lösung

laplace transformation

5 \cdot (t - 8) - 10 \cdot (t - 4)

- \frac{5}{s ^{2}}

Schritte zur Lösung

L {5 (t - 8) - 10 (t - 4)}

Schreibe

5 (t - 8) - 10 (t - 4)

um:

- 5 t

= L {- 5 t}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 5 L {t}

L {t} : \frac{1}{s ^{2}}

= - 5 \cdot \frac{1}{s ^{2}}

Fasse

- 5 \frac{1}{s ^{2}}

zusammen:

- \frac{5}{s ^{2}}

= - \frac{5}{s ^{2}}

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