en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+2y=4t

Solution

y^{^{'}} + 2 y = 4 t

Solution

y = 2 t - 1 + \frac{c _{1}}{e ^{2 t}}

Solution steps

y^{'} (t) + 2 y = 4 t

Solve linear ODE:

y = 2 t - 1 + \frac{c _{1}}{e ^{2 t}}

y = 2 t - 1 + \frac{c _{1}}{e ^{2 t}}

Popular Examples

(\partial)/(\partial y)(4x^{3y})

\frac{\partial}{\partial y} (4 x^{3 y})

3 y^{^{'}} + 4 y = e^{- x}

parity tan(5-sin(2t))parity

tan (5 - sin (2 t))

(dy)/(dx)+3x^2y=2xe^{-x^3}

\frac{d y}{d x} + 3 x^{2} y = 2 x e^{- x^{3}}

y^'+2x^{-1}y=x^{-1}sin(2x)

y^{^{'}} + 2 x^{- 1} y = x^{- 1} sin (2 x)

Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=4t ?
The solution for y^'+2y=4t is y=2t-1+(c_{1})/(e^{2t)}