integral from 0 to 1 of (2x^2)/(1+x^2)

Lösung

\int_{0}^{1} \frac{2 x ^{2}}{1 + x ^{2}} d x

2 (- \frac{π}{4} + 1)

Dezimale

0.42920 \dots

Schritte zur Lösung

\int_{0}^{1} \frac{2 x ^{2}}{1 + x ^{2}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{1} \frac{x ^{2}}{1 + x ^{2}} d x

\frac{x ^{2}}{1 + x ^{2}} = - \frac{1}{1 + x ^{2}} + 1

= 2 \cdot \int_{0}^{1} - \frac{1}{1 + x ^{2}} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (- \int_{0}^{1} \frac{1}{1 + x ^{2}} d x + \int_{0}^{1} 1 d x)

\int_{0}^{1} \frac{1}{1 + x ^{2}} d x = \frac{π}{4}

\int_{0}^{1} 1 d x = 1

= 2 (- \frac{π}{4} + 1)

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