limit as k approaches 0 of ((2z+3k)^3-4k^2z)/(2z(2z-k)^2)

解答

k \to 0 lim (\frac{( 2 z + 3 k ) ^{3} - 4 k ^{2} z}{2 z ( 2 z - k ) ^{2}})

1

求解步骤

k \to 0 lim (\frac{( 2 z + 3 k ) ^{3} - 4 k ^{2} z}{2 z ( 2 z - k ) ^{2}})

代入值

k = 0

= \frac{( 2 z + 3 \cdot 0 ) ^{3} - 4 \cdot 0 ^{2} z}{2 z ( 2 z - 0 ) ^{2}}

化简

\frac{( 2 z + 3 \cdot 0 ) ^{3} - 4 \cdot 0 ^{2} z}{2 z ( 2 z - 0 ) ^{2}} : 1

= 1

\int_{2}^{\infty} \frac{2}{x ^{2} - x} d x

\frac{d}{d x} (ln (x ln (x)))

\frac{d y}{d x} = 5^{x} ln (5) + \frac{2}{x ^{2} + 1}

t an g e n t X^{5}

y^{^{''}} + 9 y = x e^{x}