limit as x approaches 6+of (2+x)/(6-x)

解答

x \to 6 + lim (\frac{2 + x}{6 - x})

- \infty

求解步骤

x \to 6 + lim (\frac{2 + x}{6 - x})

\frac{2 + x}{6 - x} = (2 + x) \frac{1}{6 - x}

= x \to 6 + lim ((2 + x) \frac{1}{6 - x})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

不定型除外

= x \to 6 + lim (2 + x) \cdot x \to 6 + lim (\frac{1}{6 - x})

x \to 6 + lim (2 + x) = 8

x \to 6 + lim (\frac{1}{6 - x}) = - \infty

= 8 (- \infty)

运用无穷大属性:

c \cdot (- \infty) = - \infty

= - \infty

d er i v a t i v e f (x) = 3 x^{2 x + 3} + e^{2}

x \to 0 lim (e^{x} sin (x))

\int \frac{2}{x ( x ^{2} + 1 )} d x

\int y x^{2} d y

\frac{\partial}{\partial x} (3 x + 2 y)