(\partial}{\partial z}(\frac{(x+y))/z)

解答

\frac{\partial}{\partial z} (\frac{( x + y )}{z})

- \frac{x + y}{z ^{2}}

求解步骤

\frac{\partial}{\partial z} (\frac{( x + y )}{z})

将

x, y

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= (x + y) \frac{\partial}{\partial z} (\frac{1}{z})

使用指数法则:

\frac{1}{a} = a^{- 1}

= (x + y) \frac{\partial}{\partial z} (z^{- 1})

使用幂法则:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= (x + y) (- 1 \cdot z^{- 1 - 1})

化简

(x + y) (- 1 \cdot z^{- 1 - 1}) : - \frac{x + y}{z ^{2}}

= - \frac{x + y}{z ^{2}}

d er i v a t i v e y = \frac{x ^{2} - 8 x + 3}{x ^{2} + 5}

\frac{d}{d x} (ln (x^{c o s (x)}))

t an g e n t x y + 1 + e = e^{- x y}, (1, - 1)

\int 6 x y^{2} d y

t an g e n t f (x) = e^{x}, at x = ln (14)