de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

sum from n=1 to infinity of (0.2)^n

Lösung

n = 1 \sum \infty (0.2)^{n}

Lösung

0.25

Schritte zur Lösung

n = 1 \sum \infty 0. 2^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty 0. 2^{n} - 0. 2^{0}

n = 0 \sum \infty 0. 2^{n} = 1.25

= 1.25 - 0. 2^{0}

Vereinfache

= 0.25

Beliebte Beispiele

integral from pi/2 to pi of cos^2(x)

\int_{\frac{π}{2}}^{π} cos^{2} (x) d x

2 y^{^{''}} + 18 y = 0

integral of x/((3-x^2)^6)

\int \frac{x}{( 3 - x ^{2} ) ^{6}} d x

(\partial)/(\partial x)(5+xln(xy-5))

\frac{\partial}{\partial x} (5 + x ln (x y - 5))

y^{^{'}} - x y^{^{'}} = 2 x y