derivative ln(6-x^2+2x^4)

Lösung

ableitung von

ln (6 - x^{2} + 2 x^{4})

\frac{8 x ^{3} - 2 x}{6 - x ^{2} + 2 x ^{4}}

Schritte zur Lösung

\frac{d}{d x} (ln (6 - x^{2} + 2 x^{4}))

Wende die Kettenregel an:

\frac{1}{6 - x ^{2} + 2 x ^{4}} \frac{d}{d x} (6 - x^{2} + 2 x^{4})

= \frac{1}{6 - x ^{2} + 2 x ^{4}} \frac{d}{d x} (6 - x^{2} + 2 x^{4})

\frac{d}{d x} (6 - x^{2} + 2 x^{4}) = 8 x^{3} - 2 x

= \frac{1}{6 - x ^{2} + 2 x ^{4}} (8 x^{3} - 2 x)

Vereinfache

\frac{1}{6 - x ^{2} + 2 x ^{4}} (8 x^{3} - 2 x) : \frac{8 x ^{3} - 2 x}{6 - x ^{2} + 2 x ^{4}}

= \frac{8 x ^{3} - 2 x}{6 - x ^{2} + 2 x ^{4}}

\int_{1}^{\infty} \frac{7}{x ^{2} + 1} d x

d er i v a t i v e y = ((\frac{x ^{2} - 2}{2 x ^{2} + 1})^{2})

\int 6 d x

\frac{d}{d x} (∣ 2 x - 1 ∣)

\frac{\partial}{\partial x} (\frac{( x - y )}{x + y})