解答
∫(x+3)(x2+6x−7)6dx
解答
14x14+3x13+2101x12+414x11+22847x10−1251x9−238219x8−735844x7+2267533x6−61299x5−2976521x4+994014x3−21697507x2+352947x+C
求解步骤
∫(x+3)(x2+6x−7)6dx
乘开 (x+3)(x2+6x−7)6:x13+39x12+606x11+4554x10+14235x9−11259x8−152876x7−35844x6+802599x5−306495x4−1953042x3+2982042x2−1697507x+352947
=∫x13+39x12+606x11+4554x10+14235x9−11259x8−152876x7−35844x6+802599x5−306495x4−1953042x3+2982042x2−1697507x+352947dx
使用积分加法定则: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx=∫x13dx+∫39x12dx+∫606x11dx+∫4554x10dx+∫14235x9dx−∫11259x8dx−∫152876x7dx−∫35844x6dx+∫802599x5dx−∫306495x4dx−∫1953042x3dx+∫2982042x2dx−∫1697507xdx+∫352947dx
∫x13dx=14x14
∫39x12dx=3x13
∫606x11dx=2101x12
∫4554x10dx=414x11
∫14235x9dx=22847x10
∫11259x8dx=1251x9
∫152876x7dx=238219x8
∫35844x6dx=735844x7
∫802599x5dx=2267533x6
∫306495x4dx=61299x5
∫1953042x3dx=2976521x4
∫2982042x2dx=994014x3
∫1697507xdx=21697507x2
∫352947dx=352947x
=14x14+3x13+2101x12+414x11+22847x10−1251x9−238219x8−735844x7+2267533x6−61299x5−2976521x4+994014x3−21697507x2+352947x
解答补常数=14x14+3x13+2101x12+414x11+22847x10−1251x9−238219x8−735844x7+2267533x6−61299x5−2976521x4+994014x3−21697507x2+352947x+C