16y^{''}-y=0

Lösung

16 y^{^{''}} - y = 0

y = c_{1} e^{\frac{t}{4}} + c_{2} e^{- \frac{t}{4}}

Schritte zur Lösung

16 y^{''} (t) - y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{4}} + c_{2} e^{- \frac{t}{4}}

y = c_{1} e^{\frac{t}{4}} + c_{2} e^{- \frac{t}{4}}

\frac{d}{d x} (5 x 2)

\int_{1}^{2} 16 3 2 x - 3 d x

\frac{\partial}{\partial x} (x sin (v))

\frac{d}{d x} (cosh^{2} (x) - sinh^{2} (x))

d er i v a t i v e f (x) = x^{5} - x^{3} + 3