derivative f(x)=2x+sqrt(x)

Lösung

ableitung von

f (x) = 2 x + x

2 + \frac{1}{2 x}

Schritte zur Lösung

\frac{d}{d x} (2 x + x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (x)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (x) = \frac{1}{2 x}

= 2 + \frac{1}{2 x}

\frac{d}{d x} (sin (x^{2} + 3 x + 1))

d er i v a t i v e y = arcsin (x + 1)

\int \frac{2}{3} x^{\frac{3}{2}} - 9 sin (x) d x

\frac{\partial}{\partial x} (7 x sin (y - z))

x \to 8 lim (\frac{7 + 3 x - 3}{x - 8})