integral of (3x^2)/2-x-16.5

Lösung

\int \frac{3 x ^{2}}{2} - x - 16.5 d x

0.5 x^{3} - 0.5 x^{2} - 16.5 x + C

Schritte zur Lösung

\int \frac{3 x ^{2}}{2} - x - 16.5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3 x ^{2}}{2} d x - \int x d x - \int 16.5 d x

\int \frac{3 x ^{2}}{2} d x = \frac{x ^{3}}{2}

\int x d x = \frac{x ^{2}}{2}

\int 16.5 d x = 16.5 x

= \frac{x ^{3}}{2} - \frac{x ^{2}}{2} - 16.5 x

Vereinfache

= 0.5 x^{3} - 0.5 x^{2} - 16.5 x

Füge eine Konstante zur Lösung hinzu

= 0.5 x^{3} - 0.5 x^{2} - 16.5 x + C

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