(\partial)/(\partial x)(4z^2-6sin(x))

解答

\frac{\partial}{\partial x} (4 z^{2} - 6 sin (x))

- 6 cos (x)

求解步骤

\frac{\partial}{\partial x} (4 z^{2} - 6 sin (x))

将

z

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 z^{2}) - \frac{\partial}{\partial x} (6 sin (x))

\frac{\partial}{\partial x} (4 z^{2}) = 0

\frac{\partial}{\partial x} (6 sin (x)) = 6 cos (x)

= 0 - 6 cos (x)

化简

= - 6 cos (x)

\frac{\partial}{\partial x} (x y z^{2} - 18)

x \to 0 lim (\frac{x ^{2} + 8}{x - 1})

\frac{d}{d x} ((3 x - 1) (2 x + 5))

x^{^{''}} - 14 x^{^{'}} + 49 x = 4 t e^{7 t}

t an g e n t x^{3} + 4 x