5(ln(y))y^'-x^3y=0

解答

5 (ln (y)) y^{^{'}} - x^{3} y = 0

y = e^{\frac{x ^{4} + c _{1}}{10}}, y = e^{- \frac{x ^{4} + c _{1}}{10}}

求解步骤

5 (ln (y)) y^{'} (x) - x^{3} y = 0

求解可分离方程:

y = e^{\frac{x ^{4} + c _{1}}{10}}, y = e^{- \frac{x ^{4} + c _{1}}{10}}

y = e^{\frac{x ^{4} + c _{1}}{10}}, y = e^{- \frac{x ^{4} + c _{1}}{10}}

\int 8 tan (x) sec^{4} (x) d x

(tan (\frac{x}{2}))^{^{'}}

t \to 0 lim (t (ln (t)))

\int_{- 1}^{0} x 1 - x^{2} d x

\frac{d}{d x} (a (sin (x) - x cos (x)))